(a+1)x^2-2(a+3)x+2a^2-7a+3=0

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Solution for (a+1)x^2-2(a+3)x+2a^2-7a+3=0 equation: 


Simplifying
(a + 1) * x2 + -2(a + 3) * x + 2a2 + -7a + 3 = 0

Reorder the terms:
(1 + a) * x2 + -2(a + 3) * x + 2a2 + -7a + 3 = 0

Reorder the terms for easier multiplication:
x2(1 + a) + -2(a + 3) * x + 2a2 + -7a + 3 = 0
(1 * x2 + a * x2) + -2(a + 3) * x + 2a2 + -7a + 3 = 0

Reorder the terms:
(ax2 + 1x2) + -2(a + 3) * x + 2a2 + -7a + 3 = 0
(ax2 + 1x2) + -2(a + 3) * x + 2a2 + -7a + 3 = 0

Reorder the terms:
ax2 + 1x2 + -2(3 + a) * x + 2a2 + -7a + 3 = 0

Reorder the terms for easier multiplication:
ax2 + 1x2 + -2x(3 + a) + 2a2 + -7a + 3 = 0
ax2 + 1x2 + (3 * -2x + a * -2x) + 2a2 + -7a + 3 = 0

Reorder the terms:
ax2 + 1x2 + (-2ax + -6x) + 2a2 + -7a + 3 = 0
ax2 + 1x2 + (-2ax + -6x) + 2a2 + -7a + 3 = 0

Reorder the terms:
3 + -7a + -2ax + ax2 + 2a2 + -6x + 1x2 = 0

Solving
3 + -7a + -2ax + ax2 + 2a2 + -6x + 1x2 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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